Suppose z varies directly with x and inversely with the square of y. If z = 16 when x = 4 and y = 1 , what is z when x = 8 and y = 9 ?

Question

asked Aug 17, 2022 218k views

1 Answer

Bobsr · Answer 1 · 2022-08-20T21:02:58+0000

Answer:

z = 3.6

Explanation:

Given that,

z varies directly with x and inversely with the square of y. We can write it as :

$z\propto (x)/(y)\\\\z=(kx)/(y)$

Where

k is constant

Put z = 16 when x = 4 and y = 1

$16=(k* 4)/(1)\\\\k=4$

Now put k = 4, x = 8 and y = 9

$z=(4* 8)/(9)\\\\z=3.6$

So, the value of z is equal to 3.6.