Question

Calculate the mass of water produced when 1.57g of butane reacts with excess oxygen

Answer 1

Step-by-step explanation:

So, first you will want to write the balanced chemical equation for this reaction.

Butane =
`C_4H_(10)`

`2C_4H_(10)+13O_2=>10H_2O+8CO_2`

^ This ends up being your balanced chemical equation. Now, you can do the math!

`1.57gC_4H_(10)*(1molC_4H_(10))/(58.12gC_4H_(10))*(10molH_2O)/(2molC_4H_(10))*(18gH_2O)/(1molH_2O)`

After plugging this into a calculator, your final mass of water should be:

2.43gH2O