Midsegments geometry acellus pls helppfpfpff

asked Jan 24, 2022 235k views

3 votes

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2 votes

Answer:

BC = 28

Explanation:

The midsegment DF is half the measure of the third side BC , then

BC = 2 × DF = 2 × 14 = 28

Jeum answered Jan 31, 2022

by Jeum

4.0k points

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