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Two particles have positions at time t given by s1=4t-t^2 and s2=5t^2-t^3. Find the velocities

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Explanation:

Given that,

The positions of the first particle,
s_1=4t-t^2

Velocity,


v_1=(ds_1)/(dt)\\\\v_1=(d(4t-t^2))/(dt)\\\\v_1=4-2t

Position,


s_2=5t^2-t^3


v_2=(ds_2)/(dt)\\\\v_2=(d(5t^2-t^3))/(dt)\\\\v_2=10t-3t^2

Hence, this is the required solution.

User Lee Hiles
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