Answer:
B
Explanation:
> if the lines are perpendicular then their slopes are negative reciprocal so
y=mx+b , is the general form where is m = slope
y= -3x -4, old path has slope m= -3
y= (1/3)x +b , is the new path with slope m=(1/3)
>if the paths intersect at (-3,3) then this point is on the new path as well
y= (1/3)x +b, now substitute x= -3, and y=3 to find b
3 = (1/3)(-3)+b , divide -3/3
3= -1 +b, add 1 to both sides
4 = b
>the equation of the new path is
y= (1/3)x +4