32.9k views
0 votes
The product of two consecutive even integers is 36 less than 18 times their sum. Find the two integers

User Alisson
by
7.9k points

1 Answer

4 votes

Answers:

There are two possible outcomes

  • The integers are 0 and 2
  • The integers are 34 and 36

If your teacher wants only positive integers, then go for the second scenario.

=========================================================

Step-by-step explanation:

x = smaller integer

x+2 = larger integer

We can see that x+2 follows directly after x, so they are consecutive. Also, there's a gap of 2 units between the values. This is due to the phrasing "consecutive even" instead of just "consecutive".

Their product is x(x+2) = x^2+2x

Their sum is x+(x+2) = 2x+2

The product is 36 less than 18 times their sum, which means,

product = 18*(sum) - 36

x^2+2x = 18(2x+2) - 36

x^2+2x = 36x+36-36

x^2+2x = 36x

x^2+2x-36x = 0

x^2-34x = 0

x(x-34) = 0

x = 0 or x-34 = 0

x = 0 or x = 34

-------------------------------------------

If x = 0, then x+2 = 0+2 = 2

The product is x*(x+2) = 0*2 = 0

The sum is x+(x+2) = 0+2 = 2

If we multiply the sum by 18, then we get 18*2 = 36. Subtracting off 36 leads to 36-36 = 0

Therefore the equation below

product = 18*(sum) - 36

has been satisfied

-----------------------------------------

If x = 34, then x+2 = 34+2 = 36

product = x*(x+2) = 34*36 = 1224

sum = x+(x+2) = 34+36 = 70

then we can see that...

product = 18*(sum) - 36

1224 = 18*(70) - 36

1224 = 1260 - 36

1224 = 1224

So that works as well.

----------------------------------------

There are two possible outcomes

Either the integers are 0 and 2

OR

the integers are 34 and 36

User Govan
by
9.6k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.