9514 1404 393
Answer:
48 +j64 ohms
Explanation:
The impedance of a series circuit is the sum ...
R + jXl -jXc
= 48 +j100 -j36
= 48 +j64 . . . . ohms
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Additional comment
"j" is the electrical engineer's name for √-1, because "i" is used to represent current.