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Number of conducting plates of a multiplate capacitor is 5. The no. Of capacitors is

A.1
B.2
C.3
D.4
(Ans with explanation pls)

1 Answer

4 votes

Answer:

4 capacitors

Step-by-step explanation:

Given


n = 5 --- conducting plates

Required

The number of capacitor (c)

This is calculated as:


c = n - 1

So, we have:


c = 5 - 1


c = 4

User Andy Stuhl
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