1 Answer

Puggan Se · Answer 1 · 2022-09-22T15:25:12+0000

Answer:

$(a)\ n+1$

Explanation:

Given

$n \to even$

Required

Which cannot be even

To do this, we assume an even number for n;

Assume that
n = 4

So, we have:

$(a)\ n+1$

n +1 = 4 + 1 = 5 --- this is odd

$(b)\ n+2$

n +2 = 4+2 = 6 ---- this is even

$(c)\ 2n$

2n = 2 * 4 = 8 --- this is even

$(d)\ n^2$

n^2 = 4^2 = 16 --- this is even

Hence, (a) can't be even

Please log in or register to add a comment.