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2 votes
What is the solution for the following system of equations?

5x + 7y = 3
2x + 3y = 1
O (-1,2)
O (1,-2)
O (-2,1)
O (2,-1)

User Aemkei
by
9.0k points

2 Answers

3 votes

Answer:


(2, -1)

Explanation:

Given the system of equations:


\begin{cases}5x+7y=3,\\2x+3y=1\end{cases}

Multiply the first equation by -2 and the second equation by 5, then add both equations to solve for
y:


\begin{cases}-2(5x+7y)=(-2)3,\\5(2x+3y)=(5)1\end{cases},\\\begin{cases}-10x-14y=-6,\\10x+15y=5\end{cases},\\-10x+10x-14y+15y=-6+5,\\y=-1

Substitute
y=-1 into any equation to solve for
x:


2x+3y=1,\\2x+3(-1)=1,\\2x-3=1,\\2x=4,\\x=\boxed{2}

Therefore, the solution to this system of equations is
\boxed{(2, -1)}

User Alanxz
by
8.8k points
5 votes

Explanation:

I recommend you to use matrices for systems of equations; it's a lot faster and more expedient.

What is the solution for the following system of equations? 5x + 7y = 3 2x + 3y = 1 O-example-1
User Ammadu
by
8.5k points

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