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2071 Old Q.No.5 Person's coefficient of skewness for a distribution is 0.4 and its coefficient of variation is 30%. If mode is 88, find mean and median.​

User Janaz
by
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1 Answer

3 votes

Answer:


Mean = 100


Median = 96

Explanation:

Given


C_v = 30\% --- coefficient of variation


mode = 88


Skp = 0.4

Required

The mean and the median

The coefficient of variation is calculated using:


C_v = (\sigma)/(\mu)

Where:


\mu \to mean

So:


30\% = (\sigma)/(\mu)

Express percentage as decimal


0.30 = (\sigma)/(\mu)

Make
\sigma the subject


\sigma = 0.30\mu

The coefficient of skewness is calculated using:


Skp = (\mu - Mode)/(\sigma)

This gives:


0.4 = (\mu - 88)/(\sigma)

Make
\sigma the subject


\sigma = (\mu - 88)/(0.4 )

Equate both expressions for
\sigma


0.30\mu = (\mu - 88)/(0.4 )

Cross multiply


0.4*0.30\mu = \mu - 88


0.12\mu = \mu - 88

Collect like terms


0.12\mu - \mu = - 88


-0.88\mu = - 88

Divide both sides by -0.88


\mu = 100

Hence:


Mean = 100

Calculate
\sigma


\sigma = 0.30\mu


\sigma = 0.30 * 100


\sigma = 30

So:

Also, the coefficient of skewness is calculated using:


Skp = (3 * (Mean - Median))/(\sigma)


0.4= (3 * (100 - Median))/(30)

Multiply both sides by 30


0.4*30= 3 * (100 - Median)

Divide both sides by 3


0.4*10= 100 - Median


4= 100 - Median

Collect like terms


Median = 100 - 4


Median = 96

User Rasmusx
by
4.6k points