Question

Examplelt: A wall of length 10 m was to be built across an open ground. The height of the wall is 4 m and thickness of the wall is 24 cm. If this wall is to be built up with bricks whose dimensions are 24 cm x 12 cm x 8 cm, how many bricks would be required?​

Answer 1

• 4167 bricks.

Explanation :

Since the wall with all its bricks makes up the space occupied by it, we need to find the volume of the wall, which is nothing but a cuboid.

Here,

`{\qquad \dashrightarrow{ \sf{Length=10 \: m=1000 \: cm}}}`

`\qquad \dashrightarrow{ \sf{Thickness=24 \: cm}}`

`\qquad \dashrightarrow{ \sf{Height=4 m=400 \: cm}}`

Therefore,

`{\qquad \dashrightarrow{ \bf{Volume \: of \: the \: wall = length * breadth * height}}}`

`{\qquad \dashrightarrow{ \sf{Volume \: of \: the \: wall = 1000 * 24 * 400 \: {cm}^(3) }}}`

Now, each brick is a cuboid with Length = 24 cm, Breadth = 12 cm and height = 8 cm.

So,

`{\qquad \dashrightarrow{ \bf{Volume \: of \: each \: brick = length * breadth * height}}}`

`{\qquad \dashrightarrow{ \sf{Volume \: of \: each \: brick = 24 * 12 * 8 \: {cm}^(3) }}}`

So,

`{\qquad \dashrightarrow{ \bf{Volume \: of \: bricks \: required = (volume \: of \: the \: wall)/(volume \: of \: each \: brick) }}}`

`{\qquad \dashrightarrow{ \sf{Volume \: of \: bricks \: required = (1000 * 24 * 400)/(24 * 13 * 8) }}}`

`{\qquad \dashrightarrow{ \sf{Volume \: of \: bricks \: required = \bf \: 4166.6} }}`

Therefore,

• The wall requires 4167 bricks.