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F(x)=5^x+1 what’s the rate of change between x=0 and x=4

User Okky
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1 Answer

5 votes

Answer:

156

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Algebra I

  • Functions
  • Function Notation
  • Average Rate of Change:
    \displaystyle \displaystyle (f(b) - f(a))/(b - a)

Explanation:

Step 1; Define

Identify

f(x) = 5ˣ + 1

Interval x [0, 4] →b = 4, a = 0

Step 2: Find Rate of Change

  1. Substitute in variables [Average Rate of Change]:
    \displaystyle \displaystyle (f(4) - f(0))/(4 - 0)
  2. [Average Rate of Change] Substitute in x [Function f(x)]:
    \displaystyle \displaystyle ((5^4 + 1) - (5^0 + 1))/(4 - 0)
  3. (Parenthesis) Evaluate exponents:
    \displaystyle \displaystyle ((625 + 1) - (1 + 1))/(4 - 0)
  4. (Parenthesis) Add:
    \displaystyle \displaystyle (626 - 2)/(4 - 0)
  5. [Fraction] Subtract:
    \displaystyle \displaystyle (624)/(4)
  6. Divide:
    \displaystyle \displaystyle 156
User Jerry Dodge
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