Answer:
1779 veh/h
Step-by-step explanation:
Given :
Peak hour factor, PHF = 0.84
Heavy vehicle adjustment factor,
= 0.847
Analysis flow rate,
= 1250 pc/h/ln
We know that,
Analysis flow rate,
![$v_p=(v)/((PHF)(N)(F_g)(F_(HV)))$](https://img.qammunity.org/2022/formulas/engineering/college/9qznka44ztq8vqjyt5lmr0reks9mp545z6.png)
Here, v = peak hour volume
= grade adjustment factor which is 0.99 for rolling terrain.
> 1200 pc/h/ln
![$v_p=(v)/((PHF)(N)(F_g)(F_(HV)))$](https://img.qammunity.org/2022/formulas/engineering/college/9qznka44ztq8vqjyt5lmr0reks9mp545z6.png)
![$1250=(v)/((0.84)(2)(1)(0.847))$](https://img.qammunity.org/2022/formulas/engineering/college/4l1p4eie5q2ifamdrx5os68j3q0jom0l7q.png)
v = 1779 veh/h
Therefore, the peak hour volume, v = 1779 veh/h