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A four-lane divided multilane highway (two lanes in each direction) in rolling terrain has five access points per mile and 11-ft lanes with a 4-ft shoulder on the right side and 2-ft shoulder on the left. The peak-hour factor is 0.84 and the traffic stream has a heavy vehicle adjustment factor of 0.847. If the analysis flow rate is 1250 pc/h/ln, what is the peak-hour volume

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Answer:

1779 veh/h

Step-by-step explanation:

Given :

Peak hour factor, PHF = 0.84

Heavy vehicle adjustment factor,
$F_(HV)$ = 0.847

Analysis flow rate,
v_p = 1250 pc/h/ln

We know that,

Analysis flow rate,
$v_p=(v)/((PHF)(N)(F_g)(F_(HV)))$

Here, v = peak hour volume


$F_g$ = grade adjustment factor which is 0.99 for rolling terrain.

> 1200 pc/h/ln


$v_p=(v)/((PHF)(N)(F_g)(F_(HV)))$


$1250=(v)/((0.84)(2)(1)(0.847))$

v = 1779 veh/h

Therefore, the peak hour volume, v = 1779 veh/h

User Bohdan Ivanov
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