When rebuilding her car's engine, a physics major must exert 405 N of force to insert a dry steel piston into a steel cylinder. What is the magnitude of the normal force in…

Question

asked Aug 5, 2022 103k views

1 Answer

Deelaka · Answer 1 · 2022-08-11T01:07:32+0000

Answer:

N=675N

Step-by-step explanation:

From the question we are told that:

Force
F=405N

Generally the equation for Normal force in this case is is mathematically given by

$F=\mu_s N$

Where

Static Friction=
$\mu_s$

$\mu_s=0.6$

Therefore

$N=(F)/(\mu_s)$

N=(405)/(0.6)

N=675N