Question

When rebuilding her car's engine, a physics major must exert 405 N of force to insert a dry steel piston into a steel cylinder. What is the magnitude of the normal force in newtons between the piston and cylinder

Answer 1

`N=675N`

Step-by-step explanation:

From the question we are told that:

Force
`F=405N`

Generally the equation for Normal force in this case is is mathematically given by

`F=\mu_s N`

Where

Static Friction=
`\mu_s`

`\mu_s=0.6`

Therefore

`N=(F)/(\mu_s)`

`N=(405)/(0.6)`

`N=675N`