Answer: The moles of substance present is 0.1 mol and molarity of the solution is 0.4 M.
Step-by-step explanation:
Given: Mass = 4 g
Volume = 250
(1
= 0.001 L) = 0.250 L
Moles is the mass of a substance divided by its molar mass.
So, moles of NaOH (molar mass = 40 g/mol) is calculated as follows.
![Moles = (mass)/(molar mass)\\= (4 g)/(40 g/ml)\\= 0.1 mol](https://img.qammunity.org/2022/formulas/chemistry/college/38ofzxtap9s3opv21267bqkn276dvrbhfs.png)
Molarity is the number of moles of a substance present in liter of a solution.
Hence, molarity of given NaOH solution is as follows.
![Molarity = (moles)/(Volume (in L))\\= (0.1 mol)/(0.250 L)\\= 0.4 M](https://img.qammunity.org/2022/formulas/chemistry/college/776lb8wh4z1e7wo0eojpulpceuquvnng8j.png)
Thus, we can conclude that moles of substance present is 0.1 mol and molarity of the solution is 0.4 M.