Answer: The moles of substance present is 0.1 mol and molarity of the solution is 0.4 M.
Step-by-step explanation:
Given: Mass = 4 g
Volume = 250
(1
= 0.001 L) = 0.250 L
Moles is the mass of a substance divided by its molar mass.
So, moles of NaOH (molar mass = 40 g/mol) is calculated as follows.
Molarity is the number of moles of a substance present in liter of a solution.
Hence, molarity of given NaOH solution is as follows.
Thus, we can conclude that moles of substance present is 0.1 mol and molarity of the solution is 0.4 M.