Question

38. Consider the following equilibrium:

2CO(g) + O2(g) =2CO2
Keg=4.0 x 10-10
What is the value of Key for 2CO2(g) + 2COR + O2g) ?​

Answer 1

`Key=2.5x10^(-9)`

Step-by-step explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to calculate the equilibrium constant value for the reverse reaction:

`2CO_2(g) \rightleftharpoons 2CO(g) + O_2(g)`

By knowing that the equilibrium expression is actually:

`Key =([CO]^2[O_2])/([CO_2]^2) =(1)/(Keg)`

Thus, we plug in and solve for the inverse of Keq to obtain Key as follows:

`Key =(1)/(4.0x10^(-10))\\\\Key=2.5x10^(-9)`

Regards!