185k views
3 votes
Given that x^2+y^2=9 and xy=5, find the value of (x - y)^2. ​

2 Answers

3 votes

Answer:


(x -y)^2 = -1

Explanation:


(x - y)^2 = x^2 + y^2 - 2xy


= (x^2 + y^2 ) - 2(xy)\\\\=(9) - 2( 5)\\\\= 9 - 10 \\\\ = -1

User Kalish
by
8.8k points
3 votes

Solution:

The binomial expansion of (x - y)² is

(x - y)² = x² - 2xy + y²

Substitute the given values to the equation

(x - y)² = x² - 2xy + y²

(x - y)² = x² + y² - 2xy

(x - y)² = 9 - 2(5)

(x - y)² = 9 - 10

(x - y)² = -1

Therefore the value of (x - y)² is -1.

#ILoveMath

#ILoveYouShaina

User Arpl
by
8.5k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories