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Please help im desperate no. 48 and 49​

Please help im desperate no. 48 and 49​-example-1
User Wooters
by
8.2k points

2 Answers

3 votes

Answer:

C and (3, 6 )

Explanation:

(48)

Since given y = 2x the best method of solving is by substitution C

(49)

Given the 2 equations

3x + y = 15 → (1)

y = 2x → (2)

Substitute y = 2x into (1)

3x + 2x = 15

5x = 15 ( divide both sides by 5 )

x = 3

Substitute x = 3 into (2) and evaluate for y

y = 2x = 2 × 3 = 6

solution is (3, 6 )

User Pulsejet
by
8.1k points
4 votes

Answer:

48. option C : Substitution

49. Option D : ( 3, 6)

Explanation:

3x + y = 15 ------------- ( 1 )

y = 2x ------------------- ( 2 )

Substitute ( 2 ) in ( 1 ) :

3x + y = 15

3x + 2x = 15

5x = 15


x = (15)/(5) = 3

Substitute x in ( 2 ) :

y = 2x

y = 2 × 3 = 6

The solution to the system of equation is ( 3 , 6 )

User Onychomys
by
8.1k points

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