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A concert loudspeaker suspended high off the ground emits 26.0 W of sound power. A small microphone with a 1.00 cm2 area is 53.0 m from the speaker. Part A What is the sound intensity at the position of the microphone

User Jay Shin
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1 Answer

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Answer:

the sound intensity at the position of the microphone is 7.4 × 10⁻⁴ W/m²

Step-by-step explanation:

Given the data in the question;

Sound power P = 26.0 W

Area of microphone A = 1.00 cm²

Radius r = 53.0 m

sound intensity at the position of the microphone = ?

Now, intensity at the position of the microphone can be determined using the following expression;


I = P / 4πr²

We substitute


I = 26.0 / ( 4 × π × (53.0 )² )


I = 26.0 / ( 4 × π × 2809 )


I = 26.0 / 35298.935


I = 26.0 / ( 4 × π × (53.0 )² )


I = 0.000736566


I = 7.4 × 10⁻⁴ W/m²

Therefore, the sound intensity at the position of the microphone is 7.4 × 10⁻⁴ W/m²

User Slinden
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