Question

A manometer is fastened to a pipe to measure the velocity of SAE (30) oil as it flows at steady state. The manometer is designed to read the static and stagnation pressures of the flow and uses water as the gage fluid. Determine the upstream velocity V of the oil.

Answer 1

0.193 m/s

Step-by-step explanation:

Given :

Density of water = 1000
`kg/m^3`

Manometric height = 20 mm

Density of SAE(30) = 875.4
`kg/m^3`

Determining the upstream velocity of the oil, v =
`$√(2gh)$` , h = piezometric head.

`$h=\left((\rho_m)/(\rho_l)-1\right)y$`

`$h=\left((1000)/(875.4)-1\right)* (20)/(1000)$`

`$h=2.84* 10^(-3) \ m$`

Now,

`$v=\sqrt{2 * 9.81 * 2.84 * 10^(-3)}$`

= 0.193 m/s