Question

What is the reactance of a 60.0- mH inductor when connected to an AC current source that has a frequency of 180 Hz

Answer 1

The reactance of a 60.0 mH inductor connected to an AC current source with a frequency of 180 Hz is 678.6 Ω.

Step-by-step explanation:

The reactance of an inductor in an AC circuit is given by the formula:

XL = 2πfL

Where XL is the inductive reactance, f is the frequency of the AC current, and L is the inductance of the inductor.

In this case, the inductance is 60.0 mH and the frequency is 180 Hz. Plugging these values into the formula, we get:

XL = 2π(180)(60.0 x 10-3)

XL = 678.6 Ω

Therefore, the reactance of the 60.0 mH inductor at a frequency of 180 Hz is 678.6 Ω.

Answer 2

67.9 Ω

Step-by-step explanation:

L = 60 mH = 60 x 10⁻³ H = 0.060 H

f = 180 Hz, ω = 2πf = 1131 rad/s

reactance = ωL = 1131 x 0.060 = 67.9 Ω