Final answer:
The reactance of a 60.0 mH inductor connected to an AC current source with a frequency of 180 Hz is 678.6 Ω.
Step-by-step explanation:
The reactance of an inductor in an AC circuit is given by the formula:
XL = 2πfL
Where XL is the inductive reactance, f is the frequency of the AC current, and L is the inductance of the inductor.
In this case, the inductance is 60.0 mH and the frequency is 180 Hz. Plugging these values into the formula, we get:
XL = 2π(180)(60.0 x 10-3)
XL = 678.6 Ω
Therefore, the reactance of the 60.0 mH inductor at a frequency of 180 Hz is 678.6 Ω.