Question

Two blocks A and B with mA = 2.9 kg and mB = 0.87 kg are connected by a string of negligible mass. They rest on a frictionless horizontal surface. You pull on block A with a horizontal force of 6 N. Determine the tension in the string connecting the two blocks.

Answer 1

Tension = 1.38 N

Step-by-step explanation:

Given that:

Mass of block A
`m_A` = 2.9 kg

mass of block B
`m_B` = 0.87 kg

Force F = 6 N

Assume a = acceleration of the blocks.

Then:

`m_A` (a) +
`m_B` (a) = 6

2.9a + 0.87a = 6

3.77a = 6

a = 6/3.77

a = 1.59 m/s²

Suppose T to be the tension in the string.

If we take a look at the forces acting on the first block, then:

F - T =
`m_A` (a)

T = F -
`m_A` (a)

T = 6 - 2.9(1.59)

T = 6 - 4.62

T = 1.38 N