Question

How many aluminum atoms are in 2.88 g of aluminum?

Express your answer to three significant figures.

Answer 1

Step-by-step explanation:

no of Al atoms = 2.88/26.98*6.02*10^23

= 6.426*10^22

= 6.43*10^22

Answer 2

Step-by-step explanation:

1 Mole of Aluminum with mass 26.98g contains 6.02*10^23 atoms.

In 2.88g of Aluminum, there are 2.88/26.98*6.02*10^23 = 6.426*10^22 atoms.