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A ball of mass 100g thrown by a man moves at a velocity of 100m/s. what is the momentum? need the answer step by step plssss!!​ i need it fast!!!!!!!

User Anurag
by
4.9k points

2 Answers

4 votes
λ=
mv
h


λ⟶De Broglie wavelength
m=100 g=
1000
100

kg=0.1 kg
v=100 ms
−1

λ=
mv
h

=
0.1×100
6.623×10
−34


=6.626×10
−35
m
User Rameshthoomu
by
5.2k points
6 votes

Step-by-step explanation:

Mass of the ball= 100 g = 0.1 kg

Velocity of the ball before collision=10 m/s

Momentum of the ball before collision, p(i)=mv= 0.1×10=1 kgm/s

Since, ball returns back with same velocity

Therefore, velocity of ball after collision = -10 m/s (-ve sign due to opposite direction)

So, momentum of ball after collision,p(f) = 0.1 ×(-10) = -1 kgm/s

Now, Impulse generated in the ball= change in momentum= p(f)-p(i)= -1–1= -2 kgm/s

User Navneet Nandan Jha
by
5.2k points