Question

What is the final, balanced equation that is formed by combining these two half reactions?

CO
Cu-
> Cu2+
+ 2e-
NO3 + 2e + 2H
>NO2+H20
o Cu2+ + NO3 + + 4e + 2H+ -> Cu + NO3 + H20
o Cu + NO3 + 2H*
>Cu2+ + NO3 + H20
o 2Cu + NO3 + 2H+ —>2Cu?* + NO3 + H20
O Cu+ NO3 + 2H+—
+ NO2 + 2H20

Answer 1

Answer: Balanced equation that is formed by combining these two half reactions is
`Cu + NO^(-)_(3) + 2H^(+) \rightarrow Cu^(2+) + NO^(-)_(2) + H_(2)O`.

Step-by-step explanation:

A chemical equation which contains same number of atoms on both reactant and product side is called a balanced chemical equation.

For example,
`Cu \rightarrow Cu^(2+) + 2e^(-)`

`NO^(-)_(3) + 2e^(-) + 2H^(+) \rightarrow NO^(-)_(2) + H_(2)O`

On cancelling the common species from both these half-reactions, the complete balanced equation will be as follows.

`Cu + NO^(-)_(3) + 2H^(+) \rightarrow Cu^(2+) + NO^(-)_(2) + H_(2)O`

Thus, we can conclude that balanced equation that is formed by combining these two half reactions is
`Cu + NO^(-)_(3) + 2H^(+) \rightarrow Cu^(2+) + NO^(-)_(2) + H_(2)O`.