Question

A 2*8 inches wood member has a length =11 ft it's density is =30 Lb/ft^3 find the actual weight of this member in Lb

Answer 1

359.046 Ib

Step-by-step explanation:

density = m / v ---- ( 1 )

m = mass

v = volume = l * b * h

Given data :

density = 30 Ib / ft^3

l = 2 inches = 0.1667 ft

b = 8 inches = 0.6667 ft

h = 11 ft

v ( volume ) = 0.1667 * 0.6667 * 11 = 1.22 ft^3

back to equation 1

m = 30 * 1.22 = 36.6 Ib

Actual weight ( F ) = m * g

= 36.6 * 9.81 = 359.046 Ib.