Answer:
(a) $ 1191
(b) $ 1966.8
Explanation:
Principal, P= $ 10000
Rate of interest, r = 6 % per year
time, t = 3 years = 36 months
(a) Interest per year
The amount is given by
![A = P * \left ( 1+(r)/(100) \right )^(t)\\\\A = 10000 * \left ( 1+(6)/(100) \right )^(3)\\\\A = 10000 * 1.191\\\\A = 11910.2](https://img.qammunity.org/2022/formulas/mathematics/high-school/mplw66g1aqj1mcc9365hplokl2icv98pb9.png)
Interest is given by = $11910.2 - $10000 = $ 1910.6
(b) interest per month
The amount is given by
![A = P * \left ( 1+(r)/(100) \right )^(t)\\\\A = 10000 * \left ( 1+(6)/(1200) \right )^(36)\\\\A = 10000 * 1.1967\\\\A = 11966.8](https://img.qammunity.org/2022/formulas/mathematics/high-school/ttvakvzz84xotn7iqwga5xgq8euf94i3qy.png)
Interest paid is = $ 11966.8 - $ 10000 = $ 1966.8