Question

The chemical equation of rusting of iron is given

Fe + O2 → 2Fe2O3
a) Write the reactants and products in this reaction
b) Write the total number of reactant atoms
c) Can you balance the above equation?

Answer 1

`{ \tt{(a). { \bf{reactants : { \tt{iron \: and \: oxygen}}}}}} \\ { \bf{products : { \tt{iron(iii)oxide}}}} \\ \\ { \tt{(b).}} \: { \bf{1.204 * {10}^(24) \: atoms}} \\ { \tt{(c).}} \: { \tt{4Fe +3 O _(2) → 2Fe _(2)O _(3)}} \\ \\ { \underline{ \blue{ \tt{becker \: jnr}}}}`