Question

The wavelength of visible light range of 400 to 750mm .what is the corresponding range of photon energies for visible light

Answer 1

The range of the photon energies is between:

2.652 x 10⁻²⁵ J to 4.973 x 10⁻²⁵ J

Step-by-step explanation:

The energy of a photon is calculated using the following equation;

E = hf

where;

h is Planck's constant = 6.63 x 10⁻³⁴ Js

f is frequency of the photon

`E = h (c)/(\lambda) \\\\where;\\\\\lambda \ is \ the \ wavelength\\\\c \ is \ the \ speed \ of \ light \ = 3* 10^8 \ m/s\\\\When \ \lambda = 400 \ mm = 400 \ * 10^(-3) \ m\\\\E = ((6.63 * 10^(-34))(3* 10^8))/(400 * 10^(-3)) \\\\E = 4.973 * 10^(-25) \ J`

`When \ \lambda = 750 \ mm = 750 \ * 10^(-3) \ m\\\\E = ((6.63 * 10^(-34))(3* 10^8))/(750 * 10^(-3)) \\\\E = 2.652 * 10^(-25) \ J`

The range of the photon energies is between:

2.652 x 10⁻²⁵ J to 4.973 x 10⁻²⁵ J