Answer:
Width=5m
Lenght= 20m
Explanation:
L= Lenght
W= width
perimeter = (2L + 2W) ......eqn(1)
From the question, length of the rectangle is 4 times of it's width
Then
L = (4W)........eqn(2)
But perimeter = 50
Fromeqn(1)
(2L + 2W)= 50........eqn(3)
Sub eqn(1) in eqn(3)
2(4W) + 2W = 50
8W + 2W= 50
10W= 50
W=5
From (1)
L = (4W)
L= 4×5= 20
Lenght= 20