Question

A rectangular room is 4 times as long as it is wide, and its perimeter is 50 meters. Find the dimension of the room

Answer 1

Width=5m

Lenght= 20m

Explanation:

L= Lenght

W= width

perimeter = (2L + 2W) ......eqn(1)

From the question, length of the rectangle is 4 times of it's width

Then

L = (4W)........eqn(2)

But perimeter = 50

Fromeqn(1)

(2L + 2W)= 50........eqn(3)

Sub eqn(1) in eqn(3)

2(4W) + 2W = 50

8W + 2W= 50

10W= 50

W=5

From (1)

L = (4W)

L= 4×5= 20

Lenght= 20