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Solve the system of equations: y=2x+1. y=x^2+2x-8

2 Answers

1 vote

Answer:

Explanation:

User Rens
by
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3 votes

Answer:

(- 3, - 5 ) , (3, 7 )

Explanation:

Given the 2 equations

y = 2x + 1 → (1)

y = x² + 2x - 8 → (2)

Substitute y = x² + 2x - 8 into (1)

x² + 2x - 8 = 2x + 1 ( subtract 2x + 1 from both sides )

x² - 9 = 0 ( add 9 to both sides )

x² = 9 ( take the square root of both sides )

x = ±
√(9) = ± 3

Substitute these values into (1) for corresponding values of y

x = - 3 : y = 2(- 3) + 1 = - 6 + 1 = - 5 ⇒ (- 3, - 5 )

x = 3 : y = 2(3) + 1 = 6 + 1 = 7 ⇒ (3, 7 )

User Jason Newton
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