Question

Can anyone help me solve this

Answer 1

`\longrightarrow{\green{ D. \:3 {a}^(4) √(2a) }}`

`\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\red{:}}}}}`

`\pink{\large\qquad \qquad \underline{ \pmb{{ \mathbb{ \maltese \: \: Mystique35}}}}}`

Answer 2

The answer is
`3a^(4)√(2a)`

Explanation:

To simplify the radical, start by factoring 9 out of 18 for step 1. Next, for step 2, rewrite 9 as
`3^(2)`. Then, factor out
`a^(8)` for step 3. For step 4, rewrite
`a^(8)` as
`(a^(4))^(2)`. Then, for step 5, move the 2 in the radical. Rewrite
`3^(2)(a^(4))^(2)`as
`(3a^(4))^(2)` for step 6. Then, add parentheses to the radical for step 7. Finally, for step 8 pull the terms out from under the radical, and the answer is
`3a^(4)√(2a)`.

Step 1:
`\sqrt{9(2)a^(9) }`

Step 2:
`\sqrt{3^(2)*2a^(9)`

Step 3:
`\sqrt{3^(2)*2(a^(8)a) }`

Step 4:
`\sqrt{3^(2)*2((a^(4))^(2)) }`

Step 5:
`\sqrt{3^(2)(a^(4))^(2)*2a }`

Step 6:
`\sqrt{(3a^(4) )^(2)*2a }`

Step 7:
`\sqrt{(3a^(4))^(2)*(2a) }`

Step 8:
`3a^(4)√(2a)`