The nth term of a sequence is 4n^2 -n-1. What is the 11th term of the sequences?

asked May 5, 2023 14.5k views

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9 votes

Answer:

The 11th term is 472

Step-by-step Step-by-step explanation:

$t_(n) = 4 {n}^(2) - n - 1$

$t_(11) = 4 * {11}^(2) - 11 - 1$

$= 4 * 121 - 12 \\ = 484 - 12 \\ = 472$

Wilkins answered May 10, 2023

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