Question

The nth term of a sequence is 4n^2 -n-1. What is the 11th term of the sequences?

Answer 1

The 11th term is 472

Step-by-step Step-by-step explanation:

`t_(n) = 4 {n}^(2) - n - 1`

`t_(11) = 4 * {11}^(2) - 11 - 1`

`= 4 * 121 - 12 \\ = 484 - 12 \\ = 472`