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A ball is dropped from a height of 5m. After each bounce it rises to 35% of its previous height. After how many bounces does the ball reach a Height of less than 50cm?

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Answer:

After the third bounce the ball reaches a height of less than 50cm.

Explanation:

Geometric sequence:

In a geometric sequence, the quotient between consecutive terms is always the same, and it's called common ratio. The nth term of a geometric sequence is given by:


A_n = A_0(r)^(n)

In which
A_0 is the first term and r is the common ratio.

A ball is dropped from a height of 5m.

This means that
A_0 = 5

After each bounce it rises to 35% of its previous height.

This means that
r = 0.35

Thus


A_n = A_0(r)^(n)


A_n = 5(0.35)^(n)

After how many bounces does the ball reach a Height of less than 50cm?

50cm = 0.5m. This is n for which
A_n = 0.5. Thus


A_n = 5(0.35)^(n)


0.5 = 5(0.35)^(n)


(0.35)^n = (0.5)/(5)


(0.35)^n = 0.1


\log{(0.35)^n} = \log{0.1}


n\log{0.35} = \log{0.1}


n = \frac{\log{0.1}}{\log{0.35}}


n = 2.19

Rounding up:

After the third bounce the ball reaches a height of less than 50cm.

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