Answer:
G, 160 in^2
Explanation:
Let us start with the general equation to find the area of this quadrilateral, which is noticably a rhombus,
, where the two d represent the two diagonals of the rhombus.
Notice that the longer diagonal consists of two 10in. portions. Let's add them up to find the total length:
in.
Now let's find the smaller diagonal consisting of two 8 in. portions:
in.
Great! Let's plug in to solve for the area:

Therefore, the area of the quadrilateral is G, 160 in^2.
I hope this helps! Let me know if you have any questions :)