118k views
3 votes
What is the area in square inches of this quadrilateral

What is the area in square inches of this quadrilateral-example-1
User Opensas
by
8.3k points

2 Answers

5 votes

Answer:

160 in²

Explanation:

20 * 16 / 2

if we wouldn't devide with 2, we would calculate the rectangle around the quadrilateral

User Subho
by
7.5k points
6 votes

Answer:

G, 160 in^2

Explanation:

Let us start with the general equation to find the area of this quadrilateral, which is noticably a rhombus,
A=(d_1d_2)/(2), where the two d represent the two diagonals of the rhombus.

Notice that the longer diagonal consists of two 10in. portions. Let's add them up to find the total length:


10+10=20in.

Now let's find the smaller diagonal consisting of two 8 in. portions:


8+8=16in.

Great! Let's plug in to solve for the area:


A=(20*16)/(2) \\A=(320)/(2) \\A=160

Therefore, the area of the quadrilateral is G, 160 in^2.

I hope this helps! Let me know if you have any questions :)

User Nikolay Vyahhi
by
8.4k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories