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What is the area in square inches of this quadrilateral

What is the area in square inches of this quadrilateral-example-1
User Opensas
by
5.6k points

2 Answers

5 votes

Answer:

160 inĀ²

Explanation:

20 * 16 / 2

if we wouldn't devide with 2, we would calculate the rectangle around the quadrilateral

User Subho
by
4.9k points
6 votes

Answer:

G, 160 in^2

Explanation:

Let us start with the general equation to find the area of this quadrilateral, which is noticably a rhombus,
A=(d_1d_2)/(2), where the two d represent the two diagonals of the rhombus.

Notice that the longer diagonal consists of two 10in. portions. Let's add them up to find the total length:


10+10=20in.

Now let's find the smaller diagonal consisting of two 8 in. portions:


8+8=16in.

Great! Let's plug in to solve for the area:


A=(20*16)/(2) \\A=(320)/(2) \\A=160

Therefore, the area of the quadrilateral is G, 160 in^2.

I hope this helps! Let me know if you have any questions :)

User Nikolay Vyahhi
by
5.3k points
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