Question

What solutions to the following quadratic
3x^2 +15x-18=0

Answer 1

The solutions would be x1=-6 and x2= 1

Answer 2

x=-6 and x=1

Explanation:

Given that:

`3x^2+15x-18`

Now,

`3x^2+15x-18=0\\`

Using the quadratic formula where a=3, b=15, and C=-18

x=-b±
`√(b^2-4ac) /2a`

x=-15±
`{√(15^2-4(3)(-18) } /2(3)`

x=-15±
`√(441) /6`

the discriminant
`b^2-4ac>0`

So, there are two real roots

x=-15±21/6

`x=(6)/(6) \\x=1\\x=(-36)/(6) \\x=-6`

Therefore, x=-6 and x=1