Find sec A and cot B exactly if a = 8 and b = 7.

Question

asked Apr 13, 2022 88.5k views

1 Answer

Jacques Gaudin · Answer 1 · 2022-04-17T08:42:27+0000

Answer:

sec A= 1.01 and cot B =8.25

Explanation:

Given :

sec A and cotB if a =8 and b=7

Now,

=
$sec A=(1)/(cos A) \\\\(1)/(cos 8) \\\\(1)/(0.99) \\1.01$

and

$cot B=(cosB)/(sin B) \\cotB=(cos 7)/(sin7) \\cot B =(0.99)/(0.12) \\cot B =8.25$

Therefore, answer will be sec A= 1.01 and cot B =8.25