Answer:
Part 1
SE= 31.94
Part2;
The population mean tells us that what would be the mean of all the monthly rents (in dollars) of studio and one-bedroom apartments in Harrisburg, Pennsylvania, in 2007.
Part 3:
576.31, 701.51
Part4:
This means that the 95%of the interval 576.31, 701.51 will have contain the value of the population parameter mean u.
Part 5:
Yes. out of 100 , 95 of the intervals will contain the true value of population mean u .
Explanation:
Part 1
The standard error is calculated using the formula
SE = S/√n
where s is the standard deviation of the sample = $ 105.93
and n is the sample size= 11
Putting the values we get
SE= $ 105.93/ √11= 31.939
Part2;
The population mean tells us that what would be the mean of all the monthly rents (in dollars) of studio and one-bedroom apartments in Harrisburg, Pennsylvania, in 2007.
Part 3:
The z∝/2 value for 0.05 is ± 1.96
The 95 % confidence interval will be given by
x` ±z ∝/2 * s/√n
Putting the values
638.91 ± 1.96 * 31.94
638.91 ± 62.6006
576.31, 701.51
Part4:
This means that the 95%of the interval 576.31, 701.51 will have contain the value of the population parameter mean u.
Part 5:
Yes when the hypothesis testing is done and the sample mean is found to be equal to the population mean then it means that the population mean is to be found in this interval; 95% .
Or out of 100 , 95 of the intervals will contain the true value of population mean u.