Answer:
K(eq) = 15 (2 sig. figs)
Step-by-step explanation:
Rxn: CO(g) + 2H₂(g) ⇄ CH₃OH(l)
C(eq): 0.150M 0.360M 0.282M
Keq = [CH₃OH(l)]/[CO(g)][H₂(g)]
= (0.282M)/(0.150M)(0.360M)²
= 14.50617284 (calc. ans.)
= 15 (2 sig. figs.)
4.5m questions
5.9m answers