Question

PLEASE HELP ASAP

Describe, in great detail, how you would graph a line that is in slope-intercept form.

Use y=-3x+ 5 as your example.

Answer 1

Thanks it’s really helpful

Answer 2

Hi there!

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Please see the explanation below.

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Step-by-step explanation:

Recall the meanings of the variables in the slope-intercept equation.

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`\boxed{\text{\underline{Slope Intercept Form:}}}\\\\y=mx+b\\---------------\\\boxed{\text{Key:}}\\\\\rightarrow \text{m - slope}\\\rightarrow \text{b - y - intercept}`

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• We already have one point given, the y-intercept. The y-intercept of a line when given a slope intercept form equation is:
  `(0, b)`

• Using the example, we would graph the point (0,5) as our first point.

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• To graph the second point, we need to understand the meaning of slope. The slope of a line can be remembered as 'rise over run'.
• The slope for the given equation is -3.
• This means we would have to go three units down and then one unit right from the y-intercept. Our new point would be (1,2).

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• The result should be the graph attached.

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Hope this helps you. I apologize if it’s incorrect.