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Line where the slope is -2 y intercept is 1

User SkyWriter
by
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2 Answers

1 vote

We've been given to find out the equation of a line who has its slope (m) = -2 and a Y-intercept = 1. So here we have basically two things i.e,

  • Slope (m) = -2

  • Y-intercept (c) = 1

First of all we must know the unique form of equation of line which is y = mx + c which is only applicable for those who have slope and y-intercept defined in it.

Placing respective values,


:\implies\rm{y = mx + c}


:\implies\rm{y = - 2x + 1}

  • The equation of line is y = -2x + 1

ADDITIONAL INFORMATION:

1) Slope point form equation: If a line passes through point (x,y) and slope (m) then equation of line is given by,


:\implies\rm{ y - y_1 = m(x - x_1)}

2) Two point form equation: If a line passes through two distinct points A(x1,y1) and B(x2,y2) then equation of line is given by,


:\implies\rm{ (y - y_1)/(y_1 - y_2) = (x - x_1)/(x_1 - x_2) }

3) Double intercept form: If x & y intercepts of line are small 'a' and 'b' then equation of line is given by,


:\implies\rm{ (x)/(a) + (y)/(b) = 1}

User Kin Cheung
by
8.0k points
8 votes

Answer:

Explanation:

y = mx +b

Here m is slope and b is y-intercept

y = -2x + 1

User EKS
by
7.9k points

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