Answer:
The escape velocity of photon from its surface=445625.7m/s
Step-by-step explanation:
We are given that
Radius, R=240 solar radii=
1 solar radii=
Mass, m=125 solar mass=
1 solar mass=
We have to find the escape velocity of photon from its surface.
We know that escape velocity
Using the formula
Hence ,the escape velocity of photon from its surface=445625.7m/s