Answer:
The escape velocity of photon from its surface=445625.7m/s
Step-by-step explanation:
We are given that
Radius, R=240 solar radii=

1 solar radii=

Mass, m=125 solar mass=

1 solar mass=

We have to find the escape velocity of photon from its surface.
We know that escape velocity

Using the formula


Hence ,the escape velocity of photon from its surface=445625.7m/s